Planet Tan

Planet Tan

How can you get tanner in the winter without going to get a tan at Planet Tan, ect.?

it is December and i cant seem to get a tan or any darker from sitting out in the cold winter air now that its not summer, and i am really white. how can i get tanner without going to get a tan?

If it is too cold to sit outside, you would either have to go to a tanning bed or use a spray on self tanner. And overuse of either one can make you look orange or fake, so be careful.

A tan from the real sun looks best in my opinion, and I hate the winter because I can't sit out :/

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Instructional How To: Versa Spa Sunless Tanning

THE LAW OF TITIUS-BODE AND THE EQUATION OF ECOSFAR DISTRICT!

We can calculate as a semimajor axis astronomical units. The distance from the Titius-Bode and Keppler orbit in region where star´s L, I, F(gamma) is the optimal atmosphere for emerging (F(gamma) be increased by adding e- flux)

At first we calculate the vacuum of ecosfar Ce, used all around the cosmos especially in the visible Universe.

Ce = (Rj/M1) x (r1/Rj) = (Rj/M1)xtan(alfa) = 8Rj)/(M2)xtan(alfa),

Rjx=  the distance of ecosfar distric from the star of radius r(o), following,

(ro)/(Rjx) = tan(alfa)

Rjx = (tan(alfa))/(ro) = (r1)/(r(o)x(Rj)

r1 = radius of Sun

Rj = distance of earth from Sun, 1 AU, (this value has a correct value to be calculated)

r(o) = radius of visible star

M1 = mass of earth

Then we calculate Rjx, when r(o) = 0.001 m

(r(o))/(Rjx) =(r1)/8Rj) and Rjx = (r(o) x (Rj)/(r1)

Rjx = (0.001 x 150 x 10 to power of 9 m)/ (6.96 x 10 to power of 8 m) = 0.2155172 m

(r(o))/(Rjx) x (tan(alfa) = Ce

alfa = 0.265850509 (degrees)

Ce = vacuum of ecosfar distric = 3.49924582 x 10 to power of -22

Rjx = ((r(o) x tan(alfa))/(Ce) = ((r)o)) x (r(1)/(Rj))/(Ce)

= ((0.001 m x (6.96 x 10 to power of 8 m))/((150) x 10 to power of 9 m))/(Ce)

Rjx = 1.326000001 x 10 to power of 19 m (real distance of ecosfar distric)

r(o) = ((Ce x Rjx))/((tan(alfa))

r(o) = 0.001 m

So when we look at the sky the distric of the ecosfar for 2 mm:n star is lying in the distric of 0.216 m ja the real distance is Rjx = 1.32000001 x 10 to power of 19 m when M(o) = M(1).

Semimajor axis is as follows,

a = 0.4 + (0.3) x 2 to power of n = 2.8

a = (2.8) x 1,49597870 x 10 to power of 11 m

   = 4.18874036 x 10 to power of 11 m (value for planet earth)

((a(o))/(Rjx) = (a)/(Rj)

a(o) = 3.70284646481 x 10 to power of 19 m (x 1.625 10 to power of -20 = 0.60183051 m)

((a(o))/(Rjx) = tan((alfa(o)) = 2.792493573

alfa(o) = 70.2974 (degrees)

When we look at the palnet from earth, star has radius of 1 mm (visible), so this star near us is viewed from a planet orbiting alfaPeg Papiljott alfaPegScheat Keppler cones elliptic orbit whose semimajor axis is 0.60183051 m approxomately 602 mm (ie. star on the right and the left side of this distance). While viewing through a telescope you can see the blue planet alfaPeg Papiljott which is the Scheat planet.

That´s all for this time!

Antti Johannes Vaalama

 

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